Two narrow cylindrical pipes A and B have the same length. Pipe A is open at both ends and is filled with a monoatomic gas of molar mass M A . Pipe B is open at one end and closed at the other end, and is filled with a diatomic gas of molar mass M B . Both gases are at the same temperature. Given the frequency of the second harmonic of the fundamental mode in pipe A is equal to the frequency of the third harmonic of the fundamental mode in pipe B.
Now If the open end of pipe B is also closed (so that the pipe is closed at both ends). the ratio of the fundamental frequency in pipe A to that in pipe B equal to p/q (in lowest form). Find pq
Text Solution
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Frequency of second harmonic in pipe A = frequency of third harmonic in pipe B
∴ 2 
= 3 
Or 
= 
(as I A = I B )
Ratio of fundamental frequency in pipe A and in pipe B is:
= 
= 
= 
(as λ A = λ B )
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